What are the solutions to the equation 6x(x-1)=1-7x ?

The solutions to the equation 6x(x-1)=1-7x are x= 1/3 ,x=-1/2

Find the zeros of 6x(x-1)=1-7x

The zeros of 6x(x-1)=1-7x are x= 1/3 ,x=-1/2

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6 x (x - 1) = 1 - 7 x

x = \frac{1}{3}, x = - \frac{1}{2}

Decimal Notation

x = 0.33333 \dots, x = - 0.5

Solution steps

6 x (x - 1) = 1 - 7 x

Expand

6 x (x - 1) : 6 x^{2} - 6 x

6 x^{2} - 6 x = 1 - 7 x

Move

7 x

to the left side

6 x^{2} + x = 1

Move

1

to the left side

6 x^{2} + x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 6 ( - 1 )}{2 \cdot 6}

1^{2} - 4 \cdot 6 (- 1) = 5

x_{1, 2} = \frac{- 1 \pm 5}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 1 + 5}{2 \cdot 6}, x_{2} = \frac{- 1 - 5}{2 \cdot 6}

x = \frac{- 1 + 5}{2 \cdot 6} : \frac{1}{3}

x = \frac{- 1 - 5}{2 \cdot 6} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - \frac{1}{2}

x^{2} + 2 = x + 4

3 (\frac{1 + i}{1 - i})^{2} - 2 (\frac{1 - i}{1 + i})^{3}

1 + \frac{5}{2}

3 x - 2 \leq 5 x

What are the solutions to the equation 6x(x-1)=1-7x ?
The solutions to the equation 6x(x-1)=1-7x are x= 1/3 ,x=-1/2
Find the zeros of 6x(x-1)=1-7x
The zeros of 6x(x-1)=1-7x are x= 1/3 ,x=-1/2