What are the solutions to the equation (x+1)^2=16 ?

The solutions to the equation (x+1)^2=16 are x=3,x=-5

Find the zeros of (x+1)^2=16

The zeros of (x+1)^2=16 are x=3,x=-5

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(x + 1)^{2} = 16

x = 3, x = - 5

Solution steps

(x + 1)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 16 : x = 3

Solve

x + 1 = - 16 : x = - 5

The solutions to the quadratic equation are:

x = 3, x = - 5

\frac{1}{4} x - 9 = 6

- 8 \cdot - 12

4 x = 6

2 \cdot \frac{3}{2}

16 p^{4} + 4 p^{3}

What are the solutions to the equation (x+1)^2=16 ?
The solutions to the equation (x+1)^2=16 are x=3,x=-5
Find the zeros of (x+1)^2=16
The zeros of (x+1)^2=16 are x=3,x=-5