What are the solutions to the equation (3x-1)(3x+2)=2x ?

The solutions to the equation (3x-1)(3x+2)=2x are x=(-1+sqrt(73))/(18),x=(-1-sqrt(73))/(18)

Find the zeros of (3x-1)(3x+2)=2x

The zeros of (3x-1)(3x+2)=2x are x=(-1+sqrt(73))/(18),x=(-1-sqrt(73))/(18)

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(3 x - 1) (3 x + 2) = 2 x

x = \frac{- 1 + 73}{18}, x = \frac{- 1 - 73}{18}

Decimal Notation

x = 0.41911 \dots, x = - 0.53022 \dots

Solution steps

(3 x - 1) (3 x + 2) = 2 x

Expand

(3 x - 1) (3 x + 2) : 9 x^{2} + 3 x - 2

9 x^{2} + 3 x - 2 = 2 x

Move

2 x

to the left side

9 x^{2} + x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 9 ( - 2 )}{2 \cdot 9}

1^{2} - 4 \cdot 9 (- 2) = 73

x_{1, 2} = \frac{- 1 \pm 73}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 1 + 73}{2 \cdot 9}, x_{2} = \frac{- 1 - 73}{2 \cdot 9}

x = \frac{- 1 + 73}{2 \cdot 9} : \frac{- 1 + 73}{18}

x = \frac{- 1 - 73}{2 \cdot 9} : \frac{- 1 - 73}{18}

The solutions to the quadratic equation are:

x = \frac{- 1 + 73}{18}, x = \frac{- 1 - 73}{18}

5 + 2 R - 8 = - 8 R + 2 + 7 R

4 x = 4 x + 3

- 67 = 45 + 7 x

12 + 48 a

∣ x + 1 ∣ < 3

What are the solutions to the equation (3x-1)(3x+2)=2x ?
The solutions to the equation (3x-1)(3x+2)=2x are x=(-1+sqrt(73))/(18),x=(-1-sqrt(73))/(18)
Find the zeros of (3x-1)(3x+2)=2x
The zeros of (3x-1)(3x+2)=2x are x=(-1+sqrt(73))/(18),x=(-1-sqrt(73))/(18)