What are the solutions to the equation 5d^2+10d+8=2d^2 ?

The solutions to the equation 5d^2+10d+8=2d^2 are d=-4/3 ,d=-2

Find the zeros of 5d^2+10d+8=2d^2

The zeros of 5d^2+10d+8=2d^2 are d=-4/3 ,d=-2

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5 d^{2} + 10 d + 8 = 2 d^{2}

d = - \frac{4}{3}, d = - 2

Solution steps

5 d^{2} + 10 d + 8 = 2 d^{2}

Move

2 d^{2}

to the left side

3 d^{2} + 10 d + 8 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 \cdot 8}{2 \cdot 3}

1 0^{2} - 4 \cdot 3 \cdot 8 = 2

d_{1, 2} = \frac{- 10 \pm 2}{2 \cdot 3}

Separate the solutions

d_{1} = \frac{- 10 + 2}{2 \cdot 3}, d_{2} = \frac{- 10 - 2}{2 \cdot 3}

d = \frac{- 10 + 2}{2 \cdot 3} : - \frac{4}{3}

d = \frac{- 10 - 2}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

d = - \frac{4}{3}, d = - 2

x^{2} + 18 = 0

a^{2} + 12 0^{2} = 37 0^{2}

d^{2} + 2 d + 1 = 0

\frac{4}{3} π (1.95)^{3}

1 - 0.8 x + 0.15 x^{2} = 0

What are the solutions to the equation 5d^2+10d+8=2d^2 ?
The solutions to the equation 5d^2+10d+8=2d^2 are d=-4/3 ,d=-2
Find the zeros of 5d^2+10d+8=2d^2
The zeros of 5d^2+10d+8=2d^2 are d=-4/3 ,d=-2