What are the solutions to the equation z^2+9z+20=0 ?

The solutions to the equation z^2+9z+20=0 are z=-4,z=-5

Find the zeros of z^2+9z+20=0

The zeros of z^2+9z+20=0 are z=-4,z=-5

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z^{2} + 9 z + 20 = 0

z = - 4, z = - 5

Solution steps

z^{2} + 9 z + 20 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 20 = 1

z_{1, 2} = \frac{- 9 \pm 1}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 9 + 1}{2 \cdot 1}, z_{2} = \frac{- 9 - 1}{2 \cdot 1}

z = \frac{- 9 + 1}{2 \cdot 1} : - 4

z = \frac{- 9 - 1}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

z = - 4, z = - 5

w - 144 = - 11

(2 - 3 x)^{2} \leq (4 + 8 x)^{2}

5 + x - 3 x = 7 - 2 x

5 u + 15

2 - 0.7 x < 1.3 - 0.3 x

What are the solutions to the equation z^2+9z+20=0 ?
The solutions to the equation z^2+9z+20=0 are z=-4,z=-5
Find the zeros of z^2+9z+20=0
The zeros of z^2+9z+20=0 are z=-4,z=-5