What are the solutions to the equation -4x^2+17x-4=0 ?

The solutions to the equation -4x^2+17x-4=0 are x= 1/4 ,x=4

Find the zeros of -4x^2+17x-4=0

The zeros of -4x^2+17x-4=0 are x= 1/4 ,x=4

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- 4 x^{2} + 17 x - 4 = 0

x = \frac{1}{4}, x = 4

Decimal Notation

x = 0.25, x = 4

Solution steps

- 4 x^{2} + 17 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 ( - 4 ) ( - 4 )}{2 ( - 4 )}

1 7^{2} - 4 (- 4) (- 4) = 15

x_{1, 2} = \frac{- 17 \pm 15}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 17 + 15}{2 ( - 4 )}, x_{2} = \frac{- 17 - 15}{2 ( - 4 )}

x = \frac{- 17 + 15}{2 ( - 4 )} : \frac{1}{4}

x = \frac{- 17 - 15}{2 ( - 4 )} : 4

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = 4

y^{2} - 14 y + 33

3 - 2 (x + 3) = \frac{x}{3} - 5

9 a^{2} - 30 = 3 a

3 x - \frac{1}{4} = 2 x + \frac{1}{3} - \frac{5}{6}

1 2^{2} + 5^{2} = c^{2}

What are the solutions to the equation -4x^2+17x-4=0 ?
The solutions to the equation -4x^2+17x-4=0 are x= 1/4 ,x=4
Find the zeros of -4x^2+17x-4=0
The zeros of -4x^2+17x-4=0 are x= 1/4 ,x=4