What is factor 25x^4y^4-1 ?

The solution to factor 25x^4y^4-1 is (5x^2y^2+1)(5x^2y^2-1)

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factor 25x^4y^4-1

factor

25 x^{4} y^{4} - 1

(5 x^{2} y^{2} + 1) (5 x^{2} y^{2} - 1)

Solution steps

25 x^{4} y^{4} - 1

25 x^{4} y^{4} = (5 x^{2} y^{2})^{2}

1 = 1^{2}

= (5 x^{2} y^{2})^{2} - 1^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(5 x^{2} y^{2})^{2} - 1^{2} = (5 x^{2} y^{2} + 1) (5 x^{2} y^{2} - 1)

= (5 x^{2} y^{2} + 1) (5 x^{2} y^{2} - 1)

- (\frac{1}{5})^{3}

(1 - i)^{10}

\frac{x}{2} = \frac{6}{4}

0 = x^{2} + 2 x - 8

What is factor 25x^4y^4-1 ?
The solution to factor 25x^4y^4-1 is (5x^2y^2+1)(5x^2y^2-1)