What are the solutions to the equation 18=2+(y-6)^2 ?

The solutions to the equation 18=2+(y-6)^2 are y=10,y=2

Find the zeros of 18=2+(y-6)^2

The zeros of 18=2+(y-6)^2 are y=10,y=2

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18 = 2 + (y - 6)^{2}

y = 10, y = 2

Solution steps

18 = 2 + (y - 6)^{2}

Switch sides

2 + (y - 6)^{2} = 18

Move

2

to the right side

(y - 6)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y - 6 = 16 : y = 10

Solve

y - 6 = - 16 : y = 2

The solutions to the quadratic equation are:

y = 10, y = 2

9 x^{2} - 18 x - 27

24 \cdot 4

\frac{x ^{17} \cdot 1}{x ^{4} y ^{2}}

\frac{36 x ^{- 4} y ^{8}}{12 y ^{7}}

- \frac{2 ( - 3 x ^{2} - 1 )}{( x ^{2} - 1 ) ^{3}} > 0

What are the solutions to the equation 18=2+(y-6)^2 ?
The solutions to the equation 18=2+(y-6)^2 are y=10,y=2
Find the zeros of 18=2+(y-6)^2
The zeros of 18=2+(y-6)^2 are y=10,y=2