What are the solutions to the equation -9k^2-10k+21=0 ?

The solutions to the equation -9k^2-10k+21=0 are k=-(5+sqrt(214))/9 ,k=(sqrt(214)-5)/9

Find the zeros of -9k^2-10k+21=0

The zeros of -9k^2-10k+21=0 are k=-(5+sqrt(214))/9 ,k=(sqrt(214)-5)/9

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- 9 k^{2} - 10 k + 21 = 0

k = - \frac{5 + 214}{9}, k = \frac{214 - 5}{9}

Decimal Notation

k = - 2.18097 \dots, k = 1.06985 \dots

Solution steps

- 9 k^{2} - 10 k + 21 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 ( - 9 ) \cdot 21}{2 ( - 9 )}

(- 10)^{2} - 4 (- 9) \cdot 21 = 2214

k_{1, 2} = \frac{- ( - 10 ) \pm 2 214}{2 ( - 9 )}

Separate the solutions

k_{1} = \frac{- ( - 10 ) + 2 214}{2 ( - 9 )}, k_{2} = \frac{- ( - 10 ) - 2 214}{2 ( - 9 )}

k = \frac{- ( - 10 ) + 2 214}{2 ( - 9 )} : - \frac{5 + 214}{9}

k = \frac{- ( - 10 ) - 2 214}{2 ( - 9 )} : \frac{214 - 5}{9}

The solutions to the quadratic equation are:

k = - \frac{5 + 214}{9}, k = \frac{214 - 5}{9}

a^{2} - 7 ab + 10 b^{2}

4 t^{4} + 4 t^{2} + 1

\frac{x ^{2} + 6 x}{x - 4} > 0

x^{2} + 10 x + 22 = 0

20 x^{2} - 84 x + 72

What are the solutions to the equation -9k^2-10k+21=0 ?
The solutions to the equation -9k^2-10k+21=0 are k=-(5+sqrt(214))/9 ,k=(sqrt(214)-5)/9
Find the zeros of -9k^2-10k+21=0
The zeros of -9k^2-10k+21=0 are k=-(5+sqrt(214))/9 ,k=(sqrt(214)-5)/9