What are the solutions to the equation r^2+2r+18=0 ?

The solutions to the equation r^2+2r+18=0 are r=-1+sqrt(17)i,r=-1-sqrt(17)i

Find the zeros of r^2+2r+18=0

The zeros of r^2+2r+18=0 are r=-1+sqrt(17)i,r=-1-sqrt(17)i

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r^{2} + 2 r + 18 = 0

r = - 1 + 17 i, r = - 1 - 17 i

Solution steps

r^{2} + 2 r + 18 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 18 : 217 i

r_{1, 2} = \frac{- 2 \pm 2 17 i}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 2 + 2 17 i}{2 \cdot 1}, r_{2} = \frac{- 2 - 2 17 i}{2 \cdot 1}

r = \frac{- 2 + 2 17 i}{2 \cdot 1} : - 1 + 17 i

r = \frac{- 2 - 2 17 i}{2 \cdot 1} : - 1 - 17 i

The solutions to the quadratic equation are:

r = - 1 + 17 i, r = - 1 - 17 i

3 + \frac{5}{8} x \leq 5

(1 + (\frac{i}{n}))^{3}

8 f^{2} - 5 f - 4 = 0

4 + (- 1)

- 4 (y + 3) - 3 y = 2 (y + 3)

What are the solutions to the equation r^2+2r+18=0 ?
The solutions to the equation r^2+2r+18=0 are r=-1+sqrt(17)i,r=-1-sqrt(17)i
Find the zeros of r^2+2r+18=0
The zeros of r^2+2r+18=0 are r=-1+sqrt(17)i,r=-1-sqrt(17)i