What are the solutions to the equation (x+9)^2=0 ?

The solutions to the equation (x+9)^2=0 are x=-9

Find the zeros of (x+9)^2=0

The zeros of (x+9)^2=0 are x=-9

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(x + 9)^{2} = 0

x = - 9

Solution steps

(x + 9)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

x + 9 = 0 : x = - 9

The solution to the quadratic equation is:

x = - 9

6 x + 8 = - 62 - 4 x

2 \cdot (x - \frac{1}{5}) - 4 x - 1 = \frac{x}{3}

(\frac{5 x}{y})^{2} (\frac{y ^{3}}{10 x ^{2}})

x^{3} - 8 x^{2} - 2 x + 16

∣ x - 10 ∣ = 5

What are the solutions to the equation (x+9)^2=0 ?
The solutions to the equation (x+9)^2=0 are x=-9
Find the zeros of (x+9)^2=0
The zeros of (x+9)^2=0 are x=-9