What are the solutions to the equation 1/8 x^2-x-16=0 ?

The solutions to the equation 1/8 x^2-x-16=0 are x=16,x=-8

Find the zeros of 1/8 x^2-x-16=0

The zeros of 1/8 x^2-x-16=0 are x=16,x=-8

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\frac{1}{8} x^{2} - x - 16 = 0

x = 16, x = - 8

Solution steps

\frac{1}{8} x^{2} - x - 16 = 0

Multiply both sides by

8

x^{2} - 8 x - 128 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 128 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 128) = 24

x_{1, 2} = \frac{- ( - 8 ) \pm 24}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 24}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 24}{2 \cdot 1}

x = \frac{- ( - 8 ) + 24}{2 \cdot 1} : 16

x = \frac{- ( - 8 ) - 24}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 16, x = - 8

w + 5 < 8

6 p^{2} + p - 4 = 0

5 x + 2 = 2 x + 14

\frac{3}{2} \cdot \frac{1}{2}

x^{2} - 12 x + 15 = 0

What are the solutions to the equation 1/8 x^2-x-16=0 ?
The solutions to the equation 1/8 x^2-x-16=0 are x=16,x=-8
Find the zeros of 1/8 x^2-x-16=0
The zeros of 1/8 x^2-x-16=0 are x=16,x=-8