What are the solutions to the equation x^2+2x+26=0 ?

The solutions to the equation x^2+2x+26=0 are x=-1+5i,x=-1-5i

Find the zeros of x^2+2x+26=0

The zeros of x^2+2x+26=0 are x=-1+5i,x=-1-5i

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x^{2} + 2 x + 26 = 0

x = - 1 + 5 i, x = - 1 - 5 i

Solution steps

x^{2} + 2 x + 26 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 26}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 26 : 10 i

x_{1, 2} = \frac{- 2 \pm 10 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 10 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 10 i}{2 \cdot 1}

x = \frac{- 2 + 10 i}{2 \cdot 1} : - 1 + 5 i

x = \frac{- 2 - 10 i}{2 \cdot 1} : - 1 - 5 i

The solutions to the quadratic equation are:

x = - 1 + 5 i, x = - 1 - 5 i

- 5 v + 10 = - 7 v + 16

\frac{8 ^{- 5}}{8 ^{- 4}}

\frac{15 x ^{2} - 17 x - 4}{3 x ^{2} - 13 x + 12}

648

\frac{5 + i}{2 - i}

What are the solutions to the equation x^2+2x+26=0 ?
The solutions to the equation x^2+2x+26=0 are x=-1+5i,x=-1-5i
Find the zeros of x^2+2x+26=0
The zeros of x^2+2x+26=0 are x=-1+5i,x=-1-5i