What are the solutions to the equation (2148/10000)^2+(x/(10000))^2=1 ?

The solutions to the equation (2148/10000)^2+(x/(10000))^2=1 are x=4sqrt(5961631),x=-4sqrt(5961631)

Find the zeros of (2148/10000)^2+(x/(10000))^2=1

The zeros of (2148/10000)^2+(x/(10000))^2=1 are x=4sqrt(5961631),x=-4sqrt(5961631)

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(\frac{2148}{10000})^{2} + (\frac{x}{10000})^{2} = 1

x = 45961631, x = - 45961631

Decimal Notation

x = 9766.58056 \dots, x = - 9766.58056 \dots

Solution steps

(\frac{2148}{10000})^{2} + (\frac{x}{10000})^{2} = 1

Move

(\frac{2148}{10000})^{2}

to the right side

(\frac{x}{10000})^{2} = 1 - \frac{288369}{6250000}

Simplify

1 - \frac{288369}{6250000} : \frac{5961631}{6250000}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

\frac{x}{10000} = \frac{5961631}{6250000} : x = 45961631

Solve

\frac{x}{10000} = - \frac{5961631}{6250000} : x = - 45961631

The solutions to the quadratic equation are:

x = 45961631, x = - 45961631

\frac{1}{5} - 5

\frac{1}{6} (x + 6) = 11

\frac{x + 4}{x + 5} \leq 3

8 - x^{2} = 0

x^{3} + 2 x^{2} + 5 x + 10

What are the solutions to the equation (2148/10000)^2+(x/(10000))^2=1 ?
The solutions to the equation (2148/10000)^2+(x/(10000))^2=1 are x=4sqrt(5961631),x=-4sqrt(5961631)
Find the zeros of (2148/10000)^2+(x/(10000))^2=1
The zeros of (2148/10000)^2+(x/(10000))^2=1 are x=4sqrt(5961631),x=-4sqrt(5961631)