What are the solutions to the equation x^2=20+8x ?

The solutions to the equation x^2=20+8x are x=10,x=-2

Find the zeros of x^2=20+8x

The zeros of x^2=20+8x are x=10,x=-2

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x^{2} = 20 + 8 x

x = 10, x = - 2

Solution steps

x^{2} = 20 + 8 x

Move

8 x

to the left side

x^{2} - 8 x = 20

Move

20

to the left side

x^{2} - 8 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 20) = 12

x_{1, 2} = \frac{- ( - 8 ) \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 12}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 12}{2 \cdot 1}

x = \frac{- ( - 8 ) + 12}{2 \cdot 1} : 10

x = \frac{- ( - 8 ) - 12}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 10, x = - 2

4000

(i + 1)^{2}

r^{2} - f^{2}

8 b^{3} + 6 b^{2} + 3 b + 1

(6 - 3 i)^{2}

What are the solutions to the equation x^2=20+8x ?
The solutions to the equation x^2=20+8x are x=10,x=-2
Find the zeros of x^2=20+8x
The zeros of x^2=20+8x are x=10,x=-2