What are the solutions to the equation x^2+12x=9 ?

The solutions to the equation x^2+12x=9 are x=3(sqrt(5)-2),x=-3(2+sqrt(5))

Find the zeros of x^2+12x=9

The zeros of x^2+12x=9 are x=3(sqrt(5)-2),x=-3(2+sqrt(5))

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x^{2} + 12 x = 9

x = 3 (5 - 2), x = - 3 (2 + 5)

Decimal Notation

x = 0.70820 \dots, x = - 12.70820 \dots

Solution steps

x^{2} + 12 x = 9

Move

9

to the left side

x^{2} + 12 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot (- 9) = 65

x_{1, 2} = \frac{- 12 \pm 6 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 6 5}{2 \cdot 1}, x_{2} = \frac{- 12 - 6 5}{2 \cdot 1}

x = \frac{- 12 + 6 5}{2 \cdot 1} : 3 (5 - 2)

x = \frac{- 12 - 6 5}{2 \cdot 1} : - 3 (2 + 5)

The solutions to the quadratic equation are:

x = 3 (5 - 2), x = - 3 (2 + 5)

(- 1)^{- 2}

d^{2} + 8 d + 15

- 40 m - 30

ln (a + b) + ln (a - b) - 2 ln (c)

18 (\frac{π}{180})

What are the solutions to the equation x^2+12x=9 ?
The solutions to the equation x^2+12x=9 are x=3(sqrt(5)-2),x=-3(2+sqrt(5))
Find the zeros of x^2+12x=9
The zeros of x^2+12x=9 are x=3(sqrt(5)-2),x=-3(2+sqrt(5))