What is 2x^3+6<= 5x^2+x ?

The solution to 2x^3+6<= 5x^2+x is x<=-1\lor 3/2 <= x<= 2

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2x^3+6<= 5x^2+x

2 x^{3} + 6 \leq 5 x^{2} + x

x \leq - 1 or \frac{3}{2} \leq x \leq 2

Interval Notation

(- \infty, - 1] \cup [\frac{3}{2}, 2]

Decimal Notation

x \leq - 1 or 1.5 \leq x \leq 2

Solution steps

2 x^{3} + 6 \leq 5 x^{2} + x

Rewrite in standard form

2 x^{3} + 6 - x - 5 x^{2} \leq 0

Factor

2 x^{3} + 6 - x - 5 x^{2} : (x + 1) (2 x - 3) (x - 2)

(x + 1) (2 x - 3) (x - 2) \leq 0

Identify the intervals

x \leq - 1 or \frac{3}{2} \leq x \leq 2

4 - \frac{r}{3} = 5

3 x^{2} y - 2 x y

6 c - 6 = 9

2 x + 3 x = 4 x - 3

4 y = 16

What is 2x^3+6<= 5x^2+x ?
The solution to 2x^3+6<= 5x^2+x is x<=-1\lor 3/2 <= x<= 2