What are the solutions to the equation x^2-1x-6=0 ?

The solutions to the equation x^2-1x-6=0 are x=3,x=-2

Find the zeros of x^2-1x-6=0

The zeros of x^2-1x-6=0 are x=3,x=-2

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x^{2} - 1 x - 6 = 0

x = 3, x = - 2

Solution steps

x^{2} - 1 \cdot x - 6 = 0

Refine

x^{2} - x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 6) = 5

x_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 1}

x = \frac{- ( - 1 ) + 5}{2 \cdot 1} : 3

x = \frac{- ( - 1 ) - 5}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 3, x = - 2

40 x^{9} y^{8} + 24 x^{2} y^{5} + 16 x^{7} y^{2}

2 x y + x^{2} y - 6 - 3 x

x^{2} - 2 x + 6 \leq 0

- x = - 3 x^{2} + 1

x^{2} + (12 - x)^{2} = 74

What are the solutions to the equation x^2-1x-6=0 ?
The solutions to the equation x^2-1x-6=0 are x=3,x=-2
Find the zeros of x^2-1x-6=0
The zeros of x^2-1x-6=0 are x=3,x=-2