What is (3^7*3^{-4}*2^2)/(3^4*2^{-2)*4^2} ?

The solution to (3^7*3^{-4}*2^2)/(3^4*2^{-2)*4^2} is 1/3

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simplify (3^73^{-4}2^2)/(3^42^{-2)4^2}

simplify

\frac{3 ^{7} \cdot 3 ^{- 4} \cdot 2 ^{2}}{3 ^{4} \cdot 2 ^{- 2} \cdot 4 ^{2}}

\frac{1}{3}

Decimal Notation

0.33333 \dots

Solution steps

\frac{3 ^{7} \cdot 3 ^{- 4} \cdot 2 ^{2}}{3 ^{4} \cdot 2 ^{- 2} \cdot 4 ^{2}}

\frac{3 ^{7} \cdot 3 ^{- 4}}{3 ^{4}} = \frac{1}{3}

= \frac{2 ^{2}}{3 \cdot 2 ^{- 2} \cdot 4 ^{2}}

\frac{2 ^{2}}{2 ^{- 2}} = 2^{4}

= \frac{2 ^{4}}{3 \cdot 4 ^{2}}

Factor

4^{2} : 2^{4}

= \frac{2 ^{4}}{3 \cdot 2 ^{4}}

Cancel the common factor:

2^{4}

= \frac{1}{3}

\frac{5 !}{0 !}

\frac{4 m + 30}{m + 5} + \frac{m ^{2} + 8 m + 5}{m + 5}

3 (\frac{- 5 + 13}{6})^{2} = - 5 (\frac{- 5 + 13}{6})

- 8 \times (- 10) - 7 \times \frac{1}{- 1}

4 (3 - 2 x) + 3 x < 6 (4 + 2 x)

What is (3^7*3^{-4}*2^2)/(3^4*2^{-2)*4^2} ?
The solution to (3^7*3^{-4}*2^2)/(3^4*2^{-2)*4^2} is 1/3