What is the answer to (7-i(2*3-1))w=(6-i(3*2+2))w-i ?

The answer to (7-i(2*3-1))w=(6-i(3*2+2))w-i is w=-3/10-i 1/10

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(7-i(23-1))w=(6-i(32+2))w-i

(7 - i (2 \cdot 3 - 1)) w = (6 - i (3 \cdot 2 + 2)) w - i

w = - \frac{3}{10} - i \frac{1}{10}

Solution steps

(7 - i (2 \cdot 3 - 1)) w = (6 - i (3 \cdot 2 + 2)) w - i

i (3 \cdot 2 + 2) = 8 i

(7 - i (2 \cdot 3 - 1)) w = (6 - 8 i) w - i

Expand

w (6 - 8 i) : 6 w - 8 i w

7 w - 5 i w = 6 w - 8 i w - i

Expand

(7 - i (2 \cdot 3 - 1)) w : 7 w - 5 i w

7 w - 5 i w = 6 w - 8 i w - i

Subtract

6 w - 8 i w

from both sides

7 w - 5 i w - (6 w - 8 i w) = 6 w - 8 i w - i - (6 w - 8 i w)

Simplify

3 i w + w = - i

Factor

3 i w + w : (3 i + 1) w

(3 i + 1) w = - i

Divide both sides by

3 i + 1

w = - \frac{3}{10} - i \frac{1}{10}

x^{2} + 2 x + x y + 2 y

y \cdot y

2 (7 x - 3) > 12 x + 16

x + 2 = 2 x - 6

x^{2} - 6 x - 7 > 0

What is the answer to (7-i(2*3-1))w=(6-i(3*2+2))w-i ?
The answer to (7-i(2*3-1))w=(6-i(3*2+2))w-i is w=-3/10-i 1/10