What is factor y^4-81z^{12} ?

The solution to factor y^4-81z^{12} is (y^2+9z^6)(y+3z^3)(y-3z^3)

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factor y^4-81z^{12}

factor

y^{4} - 81 z^{12}

(y^{2} + 9 z^{6}) (y + 3 z^{3}) (y - 3 z^{3})

Solution steps

y^{4} - 81 z^{12}

y^{4} = (y^{2})^{2}

81 z^{12} = (9 z^{6})^{2}

= (y^{2})^{2} - (9 z^{6})^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(y^{2})^{2} - (9 z^{6})^{2} = (y^{2} + 9 z^{6}) (y^{2} - 9 z^{6})

= (y^{2} + 9 z^{6}) (y^{2} - 9 z^{6})

Factor

y^{2} - 9 z^{6} : (y + 3 z^{3}) (y - 3 z^{3})

= (y^{2} + 9 z^{6}) (y + 3 z^{3}) (y - 3 z^{3})

7 a - 7 b + 7 c - 7 d

14 \cdot (\frac{1000}{30.07})

x^{2} + 21 x - 100

lo g_{\frac{1}{2}} (8) = x

- 3 e^{x} + 10 < 8

What is factor y^4-81z^{12} ?
The solution to factor y^4-81z^{12} is (y^2+9z^6)(y+3z^3)(y-3z^3)