What are the solutions to the equation k^2-k+11=11 ?

The solutions to the equation k^2-k+11=11 are k=1,k=0

Find the zeros of k^2-k+11=11

The zeros of k^2-k+11=11 are k=1,k=0

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k^{2} - k + 11 = 11

k = 1, k = 0

Solution steps

k^{2} - k + 11 = 11

Move

11

to the left side

k^{2} - k = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot 0 = 1

k_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 1}, k_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 1}

k = \frac{- ( - 1 ) + 1}{2 \cdot 1} : 1

k = \frac{- ( - 1 ) - 1}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

k = 1, k = 0

- 2 (2)^{2}

\frac{2}{3}

\frac{3}{8} + \frac{5}{8} + \frac{2}{8}

\frac{( 1320 - 670 - 610 + 250 ) ( 85 )}{\frac{π}{32} ( 2.125 ) ^{4} ( 4000000 )}

\frac{1}{2} \cdot \frac{1}{2}

What are the solutions to the equation k^2-k+11=11 ?
The solutions to the equation k^2-k+11=11 are k=1,k=0
Find the zeros of k^2-k+11=11
The zeros of k^2-k+11=11 are k=1,k=0