What is sqrt(3x)+9<27 ?

The solution to sqrt(3x)+9<27 is 0<= x<108

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sqrt(3x)+9<27

3 x + 9 < 27

0 \leq x < 108

Interval Notation

[0, 108)

Solution steps

3 x + 9 < 27

Move

9

to the right side

3 x < 18

Square both sides

(3 x)^{2} < 1 8^{2}

Simplify

3 x < 324

Divide both sides by

3

x < 108

Find singularity points

Find non-negative values for radicals:

x \geq 0

Combine the intervals

x < 108 and x \geq 0

Merge Overlapping Intervals

0 \leq x < 108

x^{2} - x - (\frac{9.5}{ln ( 0.9 )}) = 0

∣ 7 x - 1 ∣ + 5 \geq 9

- 5 < x < 6

19 n < 19

2 x + 2 \leq 12