What are the solutions to the equation x^2+3x-3=0 ?

The solutions to the equation x^2+3x-3=0 are x=(-3+sqrt(21))/2 ,x=(-3-sqrt(21))/2

Find the zeros of x^2+3x-3=0

The zeros of x^2+3x-3=0 are x=(-3+sqrt(21))/2 ,x=(-3-sqrt(21))/2

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x^{2} + 3 x - 3 = 0

x = \frac{- 3 + 21}{2}, x = \frac{- 3 - 21}{2}

Decimal Notation

x = 0.79128 \dots, x = - 3.79128 \dots

Solution steps

x^{2} + 3 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 3) = 21

x_{1, 2} = \frac{- 3 \pm 21}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 21}{2 \cdot 1}, x_{2} = \frac{- 3 - 21}{2 \cdot 1}

x = \frac{- 3 + 21}{2 \cdot 1} : \frac{- 3 + 21}{2}

x = \frac{- 3 - 21}{2 \cdot 1} : \frac{- 3 - 21}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 21}{2}, x = \frac{- 3 - 21}{2}

- \frac{9}{6} + (- \frac{3}{5})

(x^{2} + x + 3) (x^{2} + x + 4) - 12

\frac{\frac{4}{5}}{6}

6 \cdot 4

\frac{5}{7} - \frac{3}{5}

What are the solutions to the equation x^2+3x-3=0 ?
The solutions to the equation x^2+3x-3=0 are x=(-3+sqrt(21))/2 ,x=(-3-sqrt(21))/2
Find the zeros of x^2+3x-3=0
The zeros of x^2+3x-3=0 are x=(-3+sqrt(21))/2 ,x=(-3-sqrt(21))/2