What is the answer to (-2(5x+4))/3 =-3(3x+2)-7/3 ?

The answer to (-2(5x+4))/3 =-3(3x+2)-7/3 is x=-1

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(-2(5x+4))/3 =-3(3x+2)-7/3

\frac{- 2 ( 5 x + 4 )}{3} = - 3 (3 x + 2) - \frac{7}{3}

x = - 1

Solution steps

\frac{- 2 ( 5 x + 4 )}{3} = - 3 (3 x + 2) - \frac{7}{3}

Multiply both sides by

3

- 2 (5 x + 4) = - 9 (3 x + 2) - 7

Expand

- 2 (5 x + 4) : - 10 x - 8

Expand

- 9 (3 x + 2) - 7 : - 27 x - 25

- 10 x - 8 = - 27 x - 25

Move

8

to the right side

- 10 x = - 27 x - 17

Move

27 x

to the left side

17 x = - 17

Divide both sides by

17

x = - 1

(x - 5)^{2} = - 6

X + 9 = 3

\frac{8 !}{( 8 - 2 ) ! 2 !}

\frac{\frac{b ^{2} - c ^{2}}{b c}}{\frac{b - c}{c}}

- 7 \times 7 + 9 \times \frac{- 1}{- 1}

What is the answer to (-2(5x+4))/3 =-3(3x+2)-7/3 ?
The answer to (-2(5x+4))/3 =-3(3x+2)-7/3 is x=-1
Solve for x: (-2(5x+4))/3 =-3(3x+2)-7/3
The solution is x=-1