What is the answer to (t-3)/7+(t-1)/3 =4 ?

The answer to (t-3)/7+(t-1)/3 =4 is t=10

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(t-3)/7+(t-1)/3 =4

\frac{t - 3}{7} + \frac{t - 1}{3} = 4

t = 10

Solution steps

\frac{t - 3}{7} + \frac{t - 1}{3} = 4

Multiply by LCM

3 (t - 3) + 7 (t - 1) = 84

Expand

3 (t - 3) + 7 (t - 1) : 10 t - 16

10 t - 16 = 84

Move

16

to the right side

10 t = 100

Divide both sides by

10

t = 10

a^{4} - a^{2} - 6

2 x - 1 < 3

\frac{i}{2 + i}

3 (x + 5) - 4 = x + 11

4 a^{2} + 16

What is the answer to (t-3)/7+(t-1)/3 =4 ?
The answer to (t-3)/7+(t-1)/3 =4 is t=10
Solve for t: (t-3)/7+(t-1)/3 =4
The solution is t=10