What are the solutions to the equation 3t^2-16t+26=0 ?

The solutions to the equation 3t^2-16t+26=0 are t= 8/3+i(sqrt(14))/3 ,t= 8/3-i(sqrt(14))/3

Find the zeros of 3t^2-16t+26=0

The zeros of 3t^2-16t+26=0 are t= 8/3+i(sqrt(14))/3 ,t= 8/3-i(sqrt(14))/3

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3 t^{2} - 16 t + 26 = 0

t = \frac{8}{3} + i \frac{14}{3}, t = \frac{8}{3} - i \frac{14}{3}

Solution steps

3 t^{2} - 16 t + 26 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 3 \cdot 26}{2 \cdot 3}

Simplify

(- 16)^{2} - 4 \cdot 3 \cdot 26 : 214 i

t_{1, 2} = \frac{- ( - 16 ) \pm 2 14 i}{2 \cdot 3}

Separate the solutions

t_{1} = \frac{- ( - 16 ) + 2 14 i}{2 \cdot 3}, t_{2} = \frac{- ( - 16 ) - 2 14 i}{2 \cdot 3}

t = \frac{- ( - 16 ) + 2 14 i}{2 \cdot 3} : \frac{8}{3} + i \frac{14}{3}

t = \frac{- ( - 16 ) - 2 14 i}{2 \cdot 3} : \frac{8}{3} - i \frac{14}{3}

The solutions to the quadratic equation are:

t = \frac{8}{3} + i \frac{14}{3}, t = \frac{8}{3} - i \frac{14}{3}

11 + \frac{1}{2}

4 (5 x - 6)^{2} - 31 = 5

10 - 3 x^{2} = x^{2} + 10 - x

y^{2} + 17 y + 72 = 0

42 = 8 m + 13 m

What are the solutions to the equation 3t^2-16t+26=0 ?
The solutions to the equation 3t^2-16t+26=0 are t= 8/3+i(sqrt(14))/3 ,t= 8/3-i(sqrt(14))/3
Find the zeros of 3t^2-16t+26=0
The zeros of 3t^2-16t+26=0 are t= 8/3+i(sqrt(14))/3 ,t= 8/3-i(sqrt(14))/3