What is factor (m+2)2-(m+2)+mn*(n+2)+2n(n+2) ?

The solution to factor (m+2)2-(m+2)+mn*(n+2)+2n(n+2) is (2+m)(n+1)^2

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factor (m+2)2-(m+2)+mn*(n+2)+2n(n+2)

factor

(m + 2) 2 - (m + 2) + mn \cdot (n + 2) + 2 n (n + 2)

(2 + m) (n + 1)^{2}

Solution steps

(m + 2) \cdot 2 - (m + 2) + mn (n + 2) + 2 n (n + 2)

Rewrite as

= 2 (2 + m) - 1 \cdot (2 + m) + mn (2 + n) + 2 n (2 + n)

Factor out common term

(2 + m)

= (2 + m) (2 - 1) + mn (2 + n) + 2 n (2 + n)

Factor out common term

n (2 + n)

= (2 + m) (- 1 + 2) + n (2 + n) (m + 2)

Rewrite as

= (2 + m) (- 1 + 2) + (2 + m) n (2 + n)

Factor out common term

(2 + m)

= (2 + m) (- 1 + 2 + n (2 + n))

Factor

n (n + 2) + 2 - 1 : (n + 1)^{2}

= (n + 1)^{2} (m + 2)

- 20 + 5 x > 5

x - 1 = - 5

- 2 + 4 x = 6 (x - 4)

- 5 n \leq 15

2 x - \frac{3}{5} (4 x + 20) - \frac{2}{3} (\frac{3 x}{4} + 3) = - \frac{19}{2}

What is factor (m+2)2-(m+2)+mn*(n+2)+2n(n+2) ?
The solution to factor (m+2)2-(m+2)+mn*(n+2)+2n(n+2) is (2+m)(n+1)^2