What are the solutions to the equation r^2-8r+17=0 ?

The solutions to the equation r^2-8r+17=0 are r=4+i,r=4-i

Find the zeros of r^2-8r+17=0

The zeros of r^2-8r+17=0 are r=4+i,r=4-i

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r^{2} - 8 r + 17 = 0

r = 4 + i, r = 4 - i

Solution steps

r^{2} - 8 r + 17 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 17}{2 \cdot 1}

Simplify

(- 8)^{2} - 4 \cdot 1 \cdot 17 : 2 i

r_{1, 2} = \frac{- ( - 8 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 8 ) + 2 i}{2 \cdot 1}, r_{2} = \frac{- ( - 8 ) - 2 i}{2 \cdot 1}

r = \frac{- ( - 8 ) + 2 i}{2 \cdot 1} : 4 + i

r = \frac{- ( - 8 ) - 2 i}{2 \cdot 1} : 4 - i

The solutions to the quadratic equation are:

r = 4 + i, r = 4 - i

32 - \frac{64}{3}

- - 54

x^{2} + 14 x y + 33 y^{2}

8 x - 3 (2 x - 4) = 3 (x - 6)

n^{2} + 5 < 8

What are the solutions to the equation r^2-8r+17=0 ?
The solutions to the equation r^2-8r+17=0 are r=4+i,r=4-i
Find the zeros of r^2-8r+17=0
The zeros of r^2-8r+17=0 are r=4+i,r=4-i