What are the solutions to the equation 8+8x+2x^2=0 ?

The solutions to the equation 8+8x+2x^2=0 are x=-2

Find the zeros of 8+8x+2x^2=0

The zeros of 8+8x+2x^2=0 are x=-2

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8 + 8 x + 2 x^{2} = 0

x = - 2

Solution steps

8 + 8 x + 2 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} + 8 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 \cdot 8}{2 \cdot 2}

8^{2} - 4 \cdot 2 \cdot 8 = 0

x_{1, 2} = \frac{- 8 \pm 0}{2 \cdot 2}

x = \frac{- 8}{2 \cdot 2}

\frac{- 8}{2 \cdot 2} = - 2

x = - 2

The solution to the quadratic equation is:

x = - 2

15 x^{2} + 7 x - 4

16 x + 15 > 31

7 - \frac{s}{2} > 3

22 - 20 = - 10 e^{0.693 (2)}

\frac{x}{- 2} + 3 \geq 9

What are the solutions to the equation 8+8x+2x^2=0 ?
The solutions to the equation 8+8x+2x^2=0 are x=-2
Find the zeros of 8+8x+2x^2=0
The zeros of 8+8x+2x^2=0 are x=-2