What are the solutions to the equation -x^2+5x-6=2 ?

The solutions to the equation -x^2+5x-6=2 are x= 5/2-i(sqrt(7))/2 ,x= 5/2+i(sqrt(7))/2

Find the zeros of -x^2+5x-6=2

The zeros of -x^2+5x-6=2 are x= 5/2-i(sqrt(7))/2 ,x= 5/2+i(sqrt(7))/2

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- x^{2} + 5 x - 6 = 2

x = \frac{5}{2} - i \frac{7}{2}, x = \frac{5}{2} + i \frac{7}{2}

Solution steps

- x^{2} + 5 x - 6 = 2

Move

2

to the left side

- x^{2} + 5 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 1 ) ( - 8 )}{2 ( - 1 )}

Simplify

5^{2} - 4 (- 1) (- 8) : 7 i

x_{1, 2} = \frac{- 5 \pm 7 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 5 + 7 i}{2 ( - 1 )}, x_{2} = \frac{- 5 - 7 i}{2 ( - 1 )}

x = \frac{- 5 + 7 i}{2 ( - 1 )} : \frac{5}{2} - i \frac{7}{2}

x = \frac{- 5 - 7 i}{2 ( - 1 )} : \frac{5}{2} + i \frac{7}{2}

The solutions to the quadratic equation are:

x = \frac{5}{2} - i \frac{7}{2}, x = \frac{5}{2} + i \frac{7}{2}

8 = lo g_{2} (64)

9 + x^{2} = 0

(3 x - 2 y)^{3} - (5 y + 3 x)^{3}

0 \leq x < - 1

x^{2} - 100 x + 1600 = 0

What are the solutions to the equation -x^2+5x-6=2 ?
The solutions to the equation -x^2+5x-6=2 are x= 5/2-i(sqrt(7))/2 ,x= 5/2+i(sqrt(7))/2
Find the zeros of -x^2+5x-6=2
The zeros of -x^2+5x-6=2 are x= 5/2-i(sqrt(7))/2 ,x= 5/2+i(sqrt(7))/2