What are the solutions to the equation x^2+20x+16=0 ?

The solutions to the equation x^2+20x+16=0 are x=2(sqrt(21)-5),x=-2(5+sqrt(21))

Find the zeros of x^2+20x+16=0

The zeros of x^2+20x+16=0 are x=2(sqrt(21)-5),x=-2(5+sqrt(21))

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x^{2} + 20 x + 16 = 0

x = 2 (21 - 5), x = - 2 (5 + 21)

Decimal Notation

x = - 0.83484 \dots, x = - 19.16515 \dots

Solution steps

x^{2} + 20 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot 16 = 421

x_{1, 2} = \frac{- 20 \pm 4 21}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 4 21}{2 \cdot 1}, x_{2} = \frac{- 20 - 4 21}{2 \cdot 1}

x = \frac{- 20 + 4 21}{2 \cdot 1} : 2 (21 - 5)

x = \frac{- 20 - 4 21}{2 \cdot 1} : - 2 (5 + 21)

The solutions to the quadratic equation are:

x = 2 (21 - 5), x = - 2 (5 + 21)

2 (3 y - 8) = 8

4 x + 0 = 9

8 x^{2} - 33 x + 27

\frac{3}{4} > \frac{5 - 2 x}{6} > - \frac{5}{3}

(y + 3)^{2} = 2 y + 6

What are the solutions to the equation x^2+20x+16=0 ?
The solutions to the equation x^2+20x+16=0 are x=2(sqrt(21)-5),x=-2(5+sqrt(21))
Find the zeros of x^2+20x+16=0
The zeros of x^2+20x+16=0 are x=2(sqrt(21)-5),x=-2(5+sqrt(21))