What are the solutions to the equation t^2-16=6t ?

The solutions to the equation t^2-16=6t are t=8,t=-2

Find the zeros of t^2-16=6t

The zeros of t^2-16=6t are t=8,t=-2

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t^{2} - 16 = 6 t

t = 8, t = - 2

Solution steps

t^{2} - 16 = 6 t

Move

6 t

to the left side

t^{2} - 16 - 6 t = 0

Write in the standard form

a x^{2} + b x + c = 0

t^{2} - 6 t - 16 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 16) = 10

t_{1, 2} = \frac{- ( - 6 ) \pm 10}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 6 ) + 10}{2 \cdot 1}, t_{2} = \frac{- ( - 6 ) - 10}{2 \cdot 1}

t = \frac{- ( - 6 ) + 10}{2 \cdot 1} : 8

t = \frac{- ( - 6 ) - 10}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

t = 8, t = - 2

(9 y - 14) (9 y + 14) - 60 = 0

lo g_{5} (\frac{1}{25}) = - 2

0.1 m - 1.3 m = - 2.1 - 2.7

6 a = 9 a

9 = 2 y + 5

What are the solutions to the equation t^2-16=6t ?
The solutions to the equation t^2-16=6t are t=8,t=-2
Find the zeros of t^2-16=6t
The zeros of t^2-16=6t are t=8,t=-2