What are the solutions to the equation x^2+4x-11=0 ?

The solutions to the equation x^2+4x-11=0 are x=-2+sqrt(15),x=-2-sqrt(15)

Find the zeros of x^2+4x-11=0

The zeros of x^2+4x-11=0 are x=-2+sqrt(15),x=-2-sqrt(15)

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x^{2} + 4 x - 11 = 0

x = - 2 + 15, x = - 2 - 15

Decimal Notation

x = 1.87298 \dots, x = - 5.87298 \dots

Solution steps

x^{2} + 4 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 11 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 11) = 215

x_{1, 2} = \frac{- 4 \pm 2 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 15}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 15}{2 \cdot 1}

x = \frac{- 4 + 2 15}{2 \cdot 1} : - 2 + 15

x = \frac{- 4 - 2 15}{2 \cdot 1} : - 2 - 15

The solutions to the quadratic equation are:

x = - 2 + 15, x = - 2 - 15

27 > b + 57

\frac{4}{3} π (5)^{3}

17 > 3 x + 11 \geq 2

(x + h) (x + h) (x + h)

x^{4} + 4 x^{2}

What are the solutions to the equation x^2+4x-11=0 ?
The solutions to the equation x^2+4x-11=0 are x=-2+sqrt(15),x=-2-sqrt(15)
Find the zeros of x^2+4x-11=0
The zeros of x^2+4x-11=0 are x=-2+sqrt(15),x=-2-sqrt(15)