What are the solutions to the equation 4y^2=32 ?

The solutions to the equation 4y^2=32 are y=2sqrt(2),y=-2sqrt(2)

Find the zeros of 4y^2=32

The zeros of 4y^2=32 are y=2sqrt(2),y=-2sqrt(2)

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Popular >

4 y^{2} = 32

y = 22, y = - 22

Solution steps

4 y^{2} = 32

Divide both sides by

4

y^{2} = 8

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 8, y = - 8

8 = 22

- 8 = - 22

y = 22, y = - 22

4 + ∣ 6 x + 9 ∣ = 2

9

25 + 35

(\frac{2}{3})^{- 2}

(\frac{1}{2})^{2}

What are the solutions to the equation 4y^2=32 ?
The solutions to the equation 4y^2=32 are y=2sqrt(2),y=-2sqrt(2)
Find the zeros of 4y^2=32
The zeros of 4y^2=32 are y=2sqrt(2),y=-2sqrt(2)