What are the solutions to the equation x^2+4x-2=0 ?

The solutions to the equation x^2+4x-2=0 are x=-2+sqrt(6),x=-2-sqrt(6)

Find the zeros of x^2+4x-2=0

The zeros of x^2+4x-2=0 are x=-2+sqrt(6),x=-2-sqrt(6)

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x^{2} + 4 x - 2 = 0

x = - 2 + 6, x = - 2 - 6

Solution steps

x^{2} + 4 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 2) = 26

x_{1, 2} = \frac{- 4 \pm 2 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 6}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 6}{2 \cdot 1}

x = \frac{- 4 + 2 6}{2 \cdot 1} : - 2 + 6

x = \frac{- 4 - 2 6}{2 \cdot 1} : - 2 - 6

The solutions to the quadratic equation are:

x = - 2 + 6, x = - 2 - 6

(3 x^{2})^{- 1}

\frac{1}{3} + \frac{3}{4}

- 7 x > 35

- 6 x^{2} + 5 x + 6 = 0

e^{- 1000}

What are the solutions to the equation x^2+4x-2=0 ?
The solutions to the equation x^2+4x-2=0 are x=-2+sqrt(6),x=-2-sqrt(6)
Find the zeros of x^2+4x-2=0
The zeros of x^2+4x-2=0 are x=-2+sqrt(6),x=-2-sqrt(6)