What is 8x+7(1-4x)<= 7x-3(x+3) ?

The solution to 8x+7(1-4x) = 2/3

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8x+7(1-4x)<= 7x-3(x+3)

8 x + 7 (1 - 4 x) \leq 7 x - 3 (x + 3)

x \geq \frac{2}{3}

Solution steps

8 x + 7 (1 - 4 x) \leq 7 x - 3 (x + 3)

Expand

- 3 (x + 3) : - 3 x - 9

- 20 x + 7 \leq 7 x - 3 x - 9

Add similar elements:

7 x - 3 x = 4 x

- 20 x + 7 \leq 4 x - 9

Expand

8 x + 7 (1 - 4 x) : - 20 x + 7

- 20 x + 7 \leq 4 x - 9

Move

7

to the right side

- 20 x \leq 4 x - 16

Move

4 x

to the left side

- 24 x \leq - 16

Multiply both sides by

- 1

24 x \geq 16

Divide both sides by

24

x \geq \frac{2}{3}

x^{4} - 3 x^{3} - 27 x + 81

x^{3 - 1}

4 y + 5 = 4 y - 6

- a^{4} b^{2} c + 5 a^{3} b c^{2} + a^{2} b^{3}

What is 8x+7(1-4x)<= 7x-3(x+3) ?
The solution to 8x+7(1-4x)<= 7x-3(x+3) is x>= 2/3