What are the solutions to the equation -3n(2n-7)=0 ?

The solutions to the equation -3n(2n-7)=0 are n=0,n= 7/2

Find the zeros of -3n(2n-7)=0

The zeros of -3n(2n-7)=0 are n=0,n= 7/2

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- 3 n (2 n - 7) = 0

n = 0, n = \frac{7}{2}

Solution steps

- 3 n (2 n - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

n = 0 or 2 n - 7 = 0

Solve

2 n - 7 = 0 : n = \frac{7}{2}

The solutions to the quadratic equation are:

n = 0, n = \frac{7}{2}

∣ x - 3 ∣ \geq 5

25 x^{2} y^{2} - 4 x^{2} y + 16 x^{2}

\frac{1}{x - 2 - 4} \leq 0

- \frac{1}{2} \cdot \frac{3}{5}

\frac{7 + 5 i}{1 + i}

What are the solutions to the equation -3n(2n-7)=0 ?
The solutions to the equation -3n(2n-7)=0 are n=0,n= 7/2
Find the zeros of -3n(2n-7)=0
The zeros of -3n(2n-7)=0 are n=0,n= 7/2