What is the answer to P(1+0.02)-1100=P ?

The answer to P(1+0.02)-1100=P is P=55000

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P(1+0.02)-1100=P

P (1 + 0.02) - 1100 = P

P = 55000

Solution steps

P (1 + 0.02) - 1100 = P

Add the numbers:

1 + 0.02 = 1.02

1.02 P - 1100 = P

Multiply both sides by

100

102 P - 110000 = P \cdot 100

Move

110000

to the right side

102 P = P \cdot 100 + 110000

Move

P 100

to the left side

2 P = 110000

Divide both sides by

2

P = 55000

a^{2} b^{2} + 5 abm + 6 m^{2}

2 b^{\frac{1}{2}} (3 b^{\frac{1}{2}} c^{\frac{1}{3}})^{2}

x^{3} + 3 x^{2} - 13 x - 15

6 y + 2 = - y + 16

\frac{x + 1}{3} = 3

What is the answer to P(1+0.02)-1100=P ?
The answer to P(1+0.02)-1100=P is P=55000
Solve for P: P(1+0.02)-1100=P
The solution is P=55000