What is (mn^{-4})/(p^0q^{-2)} ?

The solution to (mn^{-4})/(p^0q^{-2)} is (mq^2)/(n^4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (mn^{-4})/(p^0q^{-2)}

simplify

\frac{m n ^{- 4}}{p ^{0} q ^{- 2}}

\frac{m q ^{2}}{n ^{4}}

Solution steps

\frac{m n ^{- 4}}{p ^{0} q ^{- 2}}

Simplify

m n^{- 4} : \frac{m}{n ^{4}}

= \frac{\frac{m}{n ^{4}}}{p ^{0} q ^{- 2}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{m}{n ^{4} p ^{0} q ^{- 2}}

Simplify

n^{4} p^{0} q^{- 2} : \frac{n ^{4}}{q ^{2}}

= \frac{m}{\frac{n ^{4}}{q ^{2}}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{m q ^{2}}{n ^{4}}

3 a + 2 + 4 a = 23

5 - \frac{x}{2} = 1

z^{2} + 5 z + 6 = 0

8 x^{2} + 30 x + 25

n^{2} - 2 n

What is (mn^{-4})/(p^0q^{-2)} ?
The solution to (mn^{-4})/(p^0q^{-2)} is (mq^2)/(n^4)