What are the solutions to the equation x^2-8x=-9 ?

The solutions to the equation x^2-8x=-9 are x=4+sqrt(7),x=4-sqrt(7)

Find the zeros of x^2-8x=-9

The zeros of x^2-8x=-9 are x=4+sqrt(7),x=4-sqrt(7)

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x^{2} - 8 x = - 9

x = 4 + 7, x = 4 - 7

Decimal Notation

x = 6.64575 \dots, x = 1.35424 \dots

Solution steps

x^{2} - 8 x = - 9

Move

9

to the left side

x^{2} - 8 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 9 = 27

x_{1, 2} = \frac{- ( - 8 ) \pm 2 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 7}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 7}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 7}{2 \cdot 1} : 4 + 7

x = \frac{- ( - 8 ) - 2 7}{2 \cdot 1} : 4 - 7

The solutions to the quadratic equation are:

x = 4 + 7, x = 4 - 7

36 m^{2} + 24 mn + 4 n^{2}

\frac{( 14 \cdot 1 0 ^{9} )}{( 2 \cdot 1 0 ^{3} )}

\frac{6 3}{3}

12 < 2 x - 8 < 20

0 = x^{2} - 10 x + 25

What are the solutions to the equation x^2-8x=-9 ?
The solutions to the equation x^2-8x=-9 are x=4+sqrt(7),x=4-sqrt(7)
Find the zeros of x^2-8x=-9
The zeros of x^2-8x=-9 are x=4+sqrt(7),x=4-sqrt(7)