What is the answer to (4y+1)/3 =(3y-5)/2 ?

The answer to (4y+1)/3 =(3y-5)/2 is y=17

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(4y+1)/3 =(3y-5)/2

\frac{4 y + 1}{3} = \frac{3 y - 5}{2}

y = 17

Solution steps

\frac{4 y + 1}{3} = \frac{3 y - 5}{2}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(4 y + 1) \cdot 2 = 3 (3 y - 5)

Expand

(4 y + 1) \cdot 2 : 8 y + 2

Expand

3 (3 y - 5) : 9 y - 15

8 y + 2 = 9 y - 15

Move

2

to the right side

8 y = 9 y - 17

Move

9 y

to the left side

- y = - 17

Divide both sides by

- 1

y = 17

- 2 r^{2} + 16 r - 32

\frac{12 x y}{2 x}

- 37 + 47

\frac{x - 10}{2} - \frac{10 - x}{2} = 1

- \frac{1}{3} + 5 + 14 = 0

What is the answer to (4y+1)/3 =(3y-5)/2 ?
The answer to (4y+1)/3 =(3y-5)/2 is y=17
Solve for y: (4y+1)/3 =(3y-5)/2
The solution is y=17