What are the solutions to the equation 25x^2+20x=6 ?

The solutions to the equation 25x^2+20x=6 are x=(-2+sqrt(10))/5 ,x=-(2+sqrt(10))/5

Find the zeros of 25x^2+20x=6

The zeros of 25x^2+20x=6 are x=(-2+sqrt(10))/5 ,x=-(2+sqrt(10))/5

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25 x^{2} + 20 x = 6

x = \frac{- 2 + 10}{5}, x = - \frac{2 + 10}{5}

Solution steps

25 x^{2} + 20 x = 6

Move

6

to the left side

25 x^{2} + 20 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 25 ( - 6 )}{2 \cdot 25}

2 0^{2} - 4 \cdot 25 (- 6) = 1010

x_{1, 2} = \frac{- 20 \pm 10 10}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- 20 + 10 10}{2 \cdot 25}, x_{2} = \frac{- 20 - 10 10}{2 \cdot 25}

x = \frac{- 20 + 10 10}{2 \cdot 25} : \frac{- 2 + 10}{5}

x = \frac{- 20 - 10 10}{2 \cdot 25} : - \frac{2 + 10}{5}

The solutions to the quadratic equation are:

x = \frac{- 2 + 10}{5}, x = - \frac{2 + 10}{5}

5 x^{2} - 14 x - 3

(12 + 4 i) - (3 - 7 i)

(3 + 5) (3 - 5)

9 x = 120

- 3 x + 3 < 15

What are the solutions to the equation 25x^2+20x=6 ?
The solutions to the equation 25x^2+20x=6 are x=(-2+sqrt(10))/5 ,x=-(2+sqrt(10))/5
Find the zeros of 25x^2+20x=6
The zeros of 25x^2+20x=6 are x=(-2+sqrt(10))/5 ,x=-(2+sqrt(10))/5