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Popular >

t^2+t+1=(t-1)^2

Solution

t^{2} + t + 1 = (t - 1)^{2}

Solution

t = 0

Solution steps

t^{2} + t + 1 = (t - 1)^{2}

Expand

(t - 1)^{2} : t^{2} - 2 t + 1

t^{2} + t + 1 = t^{2} - 2 t + 1

Move

1

to the right side

t^{2} + t = t^{2} - 2 t

Subtract

t^{2} - 2 t

from both sides

t^{2} + t - (t^{2} - 2 t) = t^{2} - 2 t - (t^{2} - 2 t)

Simplify

3 t = 0

Divide both sides by

3

t = 0

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2 b^{3} + b^{5}

2 s \geq 6

29 x - 29 = 29 x - 11

- 3 = - 6 - (x + 15)

simplify (3*4^{10})*(l/(3^{10)})simplify

(3 \cdot 4^{10}) \cdot (\frac{l}{3 ^{10}})

Frequently Asked Questions (FAQ)

What is the answer to t^2+t+1=(t-1)^2 ?
The answer to t^2+t+1=(t-1)^2 is t=0
Solve for t: t^2+t+1=(t-1)^2
The solution is t=0