What are the solutions to the equation 6x^2-9x+2=0 ?

The solutions to the equation 6x^2-9x+2=0 are x=(9+sqrt(33))/(12),x=(9-sqrt(33))/(12)

Find the zeros of 6x^2-9x+2=0

The zeros of 6x^2-9x+2=0 are x=(9+sqrt(33))/(12),x=(9-sqrt(33))/(12)

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6 x^{2} - 9 x + 2 = 0

x = \frac{9 + 33}{12}, x = \frac{9 - 33}{12}

Decimal Notation

x = 1.22871 \dots, x = 0.27128 \dots

Solution steps

6 x^{2} - 9 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 6 \cdot 2}{2 \cdot 6}

(- 9)^{2} - 4 \cdot 6 \cdot 2 = 33

x_{1, 2} = \frac{- ( - 9 ) \pm 33}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 33}{2 \cdot 6}, x_{2} = \frac{- ( - 9 ) - 33}{2 \cdot 6}

x = \frac{- ( - 9 ) + 33}{2 \cdot 6} : \frac{9 + 33}{12}

x = \frac{- ( - 9 ) - 33}{2 \cdot 6} : \frac{9 - 33}{12}

The solutions to the quadratic equation are:

x = \frac{9 + 33}{12}, x = \frac{9 - 33}{12}

4 (6 x - 10) = 8 x + 40

\frac{1}{2} x + 5 = \frac{3}{10} x

(x - 2)^{2} = 25

\frac{2}{x - 4} \geq \frac{- 6}{5 - x}

\frac{3 - 4 i}{4 + 3 i}

What are the solutions to the equation 6x^2-9x+2=0 ?
The solutions to the equation 6x^2-9x+2=0 are x=(9+sqrt(33))/(12),x=(9-sqrt(33))/(12)
Find the zeros of 6x^2-9x+2=0
The zeros of 6x^2-9x+2=0 are x=(9+sqrt(33))/(12),x=(9-sqrt(33))/(12)