What are the solutions to the equation 25x^2=48-10x ?

The solutions to the equation 25x^2=48-10x are x= 6/5 ,x=-8/5

Find the zeros of 25x^2=48-10x

The zeros of 25x^2=48-10x are x= 6/5 ,x=-8/5

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25 x^{2} = 48 - 10 x

x = \frac{6}{5}, x = - \frac{8}{5}

Solution steps

25 x^{2} = 48 - 10 x

Move

10 x

to the left side

25 x^{2} + 10 x = 48

Move

48

to the left side

25 x^{2} + 10 x - 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 25 ( - 48 )}{2 \cdot 25}

1 0^{2} - 4 \cdot 25 (- 48) = 70

x_{1, 2} = \frac{- 10 \pm 70}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- 10 + 70}{2 \cdot 25}, x_{2} = \frac{- 10 - 70}{2 \cdot 25}

x = \frac{- 10 + 70}{2 \cdot 25} : \frac{6}{5}

x = \frac{- 10 - 70}{2 \cdot 25} : - \frac{8}{5}

The solutions to the quadratic equation are:

x = \frac{6}{5}, x = - \frac{8}{5}

x (1 + x) = 6

∣ x - 2 ∣ = 3 x + 1

\frac{5 ^{6}}{5}

\frac{1}{3} x - \frac{5}{6} = - \frac{2}{3}

e^{- 2 l n (4)}

What are the solutions to the equation 25x^2=48-10x ?
The solutions to the equation 25x^2=48-10x are x= 6/5 ,x=-8/5
Find the zeros of 25x^2=48-10x
The zeros of 25x^2=48-10x are x= 6/5 ,x=-8/5