What is (4a^2b)(3b^2-a+b/(2a^2)) ?

The solution to (4a^2b)(3b^2-a+b/(2a^2)) is 2b(6b^2a^2-2a^3+b)

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simplify (4a^2b)(3b^2-a+b/(2a^2))

simplify

(4 a^{2} b) (3 b^{2} - a + \frac{b}{2 a ^{2}})

2 b (6 b^{2} a^{2} - 2 a^{3} + b)

Solution steps

(4 a^{2} b) (3 b^{2} - a + \frac{b}{2 a ^{2}})

Join

3 b^{2} - a + \frac{b}{2 a ^{2}} : \frac{6 b ^{2} a ^{2} - 2 a ^{3} + b}{2 a ^{2}}

= 4 a^{2} b \frac{6 b ^{2} a ^{2} - 2 a ^{3} + b}{2 a ^{2}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{4 a ^{2} b ( 6 b ^{2} a ^{2} - 2 a ^{3} + b )}{2 a ^{2}}

Cancel the common factor:

a^{2}

= \frac{4 b ( 6 b ^{2} a ^{2} - 2 a ^{3} + b )}{2}

Divide the numbers:

\frac{4}{2} = 2

= 2 b (6 b^{2} a^{2} - 2 a^{3} + b)

x^{4} - 10 x^{2} + 25

x (x - 2) (x + 5) > 0

(\frac{3}{2})^{8}

\frac{100 !}{35 ! 20 ! 25 ! 20 !}

5 (6) - \frac{6}{2}

What is (4a^2b)(3b^2-a+b/(2a^2)) ?
The solution to (4a^2b)(3b^2-a+b/(2a^2)) is 2b(6b^2a^2-2a^3+b)