What are the solutions to the equation 2x^2-3=253 ?

The solutions to the equation 2x^2-3=253 are x=8sqrt(2),x=-8sqrt(2)

Find the zeros of 2x^2-3=253

The zeros of 2x^2-3=253 are x=8sqrt(2),x=-8sqrt(2)

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2 x^{2} - 3 = 253

x = 82, x = - 82

Solution steps

2 x^{2} - 3 = 253

Move

3

to the right side

2 x^{2} = 256

Divide both sides by

2

x^{2} = 128

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 128, x = - 128

128 = 82

- 128 = - 82

x = 82, x = - 82

C a (s) + M g C l^{2} (a p)

80 - x + 145 = 135

ln (2) e^{l n (2)}

3 (x - 1)^{2} = (2 x + 5)

q + \frac{5}{9} = \frac{1}{6}

What are the solutions to the equation 2x^2-3=253 ?
The solutions to the equation 2x^2-3=253 are x=8sqrt(2),x=-8sqrt(2)
Find the zeros of 2x^2-3=253
The zeros of 2x^2-3=253 are x=8sqrt(2),x=-8sqrt(2)