What are the solutions to the equation r^2+2r+2=0 ?

The solutions to the equation r^2+2r+2=0 are r=-1+i,r=-1-i

Find the zeros of r^2+2r+2=0

The zeros of r^2+2r+2=0 are r=-1+i,r=-1-i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

r^{2} + 2 r + 2 = 0

r = - 1 + i, r = - 1 - i

Solution steps

r^{2} + 2 r + 2 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 2 : 2 i

r_{1, 2} = \frac{- 2 \pm 2 i}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 2 + 2 i}{2 \cdot 1}, r_{2} = \frac{- 2 - 2 i}{2 \cdot 1}

r = \frac{- 2 + 2 i}{2 \cdot 1} : - 1 + i

r = \frac{- 2 - 2 i}{2 \cdot 1} : - 1 - i

The solutions to the quadratic equation are:

r = - 1 + i, r = - 1 - i

\frac{3 π}{2} \cdot 3

2^{3^{2}}

x^{2} - 4 + 4 = 0

2 - 16 = 0

2 x^{2} + x - 1 \leq 0

What are the solutions to the equation r^2+2r+2=0 ?
The solutions to the equation r^2+2r+2=0 are r=-1+i,r=-1-i
Find the zeros of r^2+2r+2=0
The zeros of r^2+2r+2=0 are r=-1+i,r=-1-i