What are the solutions to the equation -2x^2+8x+10=0 ?

The solutions to the equation -2x^2+8x+10=0 are x=-1,x=5

Find the zeros of -2x^2+8x+10=0

The zeros of -2x^2+8x+10=0 are x=-1,x=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 2 x^{2} + 8 x + 10 = 0

x = - 1, x = 5

Solution steps

- 2 x^{2} + 8 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 2 ) \cdot 10}{2 ( - 2 )}

8^{2} - 4 (- 2) \cdot 10 = 12

x_{1, 2} = \frac{- 8 \pm 12}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 8 + 12}{2 ( - 2 )}, x_{2} = \frac{- 8 - 12}{2 ( - 2 )}

x = \frac{- 8 + 12}{2 ( - 2 )} : - 1

x = \frac{- 8 - 12}{2 ( - 2 )} : 5

The solutions to the quadratic equation are:

x = - 1, x = 5

∣ x + 1 ∣ > 3

\frac{ln ( 2 )}{ln ( 4 )}

∣ 3 - 2 x ∣ \geq 4

\frac{4}{n - 2} + \frac{2}{4 n - 4}

- (\frac{5}{4})^{4}

What are the solutions to the equation -2x^2+8x+10=0 ?
The solutions to the equation -2x^2+8x+10=0 are x=-1,x=5
Find the zeros of -2x^2+8x+10=0
The zeros of -2x^2+8x+10=0 are x=-1,x=5